Find Probability from Z-Score
Enter a z-score to find the cumulative probability P(Z ≤ z)
What this table reports
This is a left-cumulative standard normal table: Φ(z) = P(Z ≤ z). It reports the area below z for Z with mean 0 and SD 1. At z = 0, the result is 0.5; at a positive z, it is greater than 0.5.
Other tables report the upper tail or the area from zero to z. Check the convention before using a number. Standardizing a nonnormal variable does not justify treating it as standard normal.
Read a positive z-score
For z = 1.23, choose row 1.2 and column 0.03. The cumulative probability is 0.8907. That answers “below 1.23.” The probability above it is 1 − 0.8907 = 0.1093.
The printable grid below gives Φ(z), rounded to four decimal places. The interactive lookup above also handles negative inputs and different regions.
Positive z grid: P(Z ≤ z)
| z | 0.00 | 0.01 | 0.02 | 0.03 | 0.04 | 0.05 | 0.06 | 0.07 | 0.08 | 0.09 |
|---|---|---|---|---|---|---|---|---|---|---|
| 0.0 | 0.5000 | 0.5040 | 0.5080 | 0.5120 | 0.5160 | 0.5199 | 0.5239 | 0.5279 | 0.5319 | 0.5359 |
| 0.1 | 0.5398 | 0.5438 | 0.5478 | 0.5517 | 0.5557 | 0.5596 | 0.5636 | 0.5675 | 0.5714 | 0.5753 |
| 0.2 | 0.5793 | 0.5832 | 0.5871 | 0.5910 | 0.5948 | 0.5987 | 0.6026 | 0.6064 | 0.6103 | 0.6141 |
| 0.3 | 0.6179 | 0.6217 | 0.6255 | 0.6293 | 0.6331 | 0.6368 | 0.6406 | 0.6443 | 0.6480 | 0.6517 |
| 0.4 | 0.6554 | 0.6591 | 0.6628 | 0.6664 | 0.6700 | 0.6736 | 0.6772 | 0.6808 | 0.6844 | 0.6879 |
| 0.5 | 0.6915 | 0.6950 | 0.6985 | 0.7019 | 0.7054 | 0.7088 | 0.7123 | 0.7157 | 0.7190 | 0.7224 |
| 0.6 | 0.7257 | 0.7291 | 0.7324 | 0.7357 | 0.7389 | 0.7422 | 0.7454 | 0.7486 | 0.7517 | 0.7549 |
| 0.7 | 0.7580 | 0.7611 | 0.7642 | 0.7673 | 0.7704 | 0.7734 | 0.7764 | 0.7794 | 0.7823 | 0.7852 |
| 0.8 | 0.7881 | 0.7910 | 0.7939 | 0.7967 | 0.7995 | 0.8023 | 0.8051 | 0.8078 | 0.8106 | 0.8133 |
| 0.9 | 0.8159 | 0.8186 | 0.8212 | 0.8238 | 0.8264 | 0.8289 | 0.8315 | 0.8340 | 0.8365 | 0.8389 |
| 1.0 | 0.8413 | 0.8438 | 0.8461 | 0.8485 | 0.8508 | 0.8531 | 0.8554 | 0.8577 | 0.8599 | 0.8621 |
| 1.1 | 0.8643 | 0.8665 | 0.8686 | 0.8708 | 0.8729 | 0.8749 | 0.8770 | 0.8790 | 0.8810 | 0.8830 |
| 1.2 | 0.8849 | 0.8869 | 0.8888 | 0.8907 | 0.8925 | 0.8944 | 0.8962 | 0.8980 | 0.8997 | 0.9015 |
| 1.3 | 0.9032 | 0.9049 | 0.9066 | 0.9082 | 0.9099 | 0.9115 | 0.9131 | 0.9147 | 0.9162 | 0.9177 |
| 1.4 | 0.9192 | 0.9207 | 0.9222 | 0.9236 | 0.9251 | 0.9265 | 0.9279 | 0.9292 | 0.9306 | 0.9319 |
| 1.5 | 0.9332 | 0.9345 | 0.9357 | 0.9370 | 0.9382 | 0.9394 | 0.9406 | 0.9418 | 0.9429 | 0.9441 |
| 1.6 | 0.9452 | 0.9463 | 0.9474 | 0.9484 | 0.9495 | 0.9505 | 0.9515 | 0.9525 | 0.9535 | 0.9545 |
| 1.7 | 0.9554 | 0.9564 | 0.9573 | 0.9582 | 0.9591 | 0.9599 | 0.9608 | 0.9616 | 0.9625 | 0.9633 |
| 1.8 | 0.9641 | 0.9649 | 0.9656 | 0.9664 | 0.9671 | 0.9678 | 0.9686 | 0.9693 | 0.9699 | 0.9706 |
| 1.9 | 0.9713 | 0.9719 | 0.9726 | 0.9732 | 0.9738 | 0.9744 | 0.9750 | 0.9756 | 0.9761 | 0.9767 |
| 2.0 | 0.9772 | 0.9778 | 0.9783 | 0.9788 | 0.9793 | 0.9798 | 0.9803 | 0.9808 | 0.9812 | 0.9817 |
| 2.1 | 0.9821 | 0.9826 | 0.9830 | 0.9834 | 0.9838 | 0.9842 | 0.9846 | 0.9850 | 0.9854 | 0.9857 |
| 2.2 | 0.9861 | 0.9864 | 0.9868 | 0.9871 | 0.9875 | 0.9878 | 0.9881 | 0.9884 | 0.9887 | 0.9890 |
| 2.3 | 0.9893 | 0.9896 | 0.9898 | 0.9901 | 0.9904 | 0.9906 | 0.9909 | 0.9911 | 0.9913 | 0.9916 |
| 2.4 | 0.9918 | 0.9920 | 0.9922 | 0.9925 | 0.9927 | 0.9929 | 0.9931 | 0.9932 | 0.9934 | 0.9936 |
| 2.5 | 0.9938 | 0.9940 | 0.9941 | 0.9943 | 0.9945 | 0.9946 | 0.9948 | 0.9949 | 0.9951 | 0.9952 |
| 2.6 | 0.9953 | 0.9955 | 0.9956 | 0.9957 | 0.9959 | 0.9960 | 0.9961 | 0.9962 | 0.9963 | 0.9964 |
| 2.7 | 0.9965 | 0.9966 | 0.9967 | 0.9968 | 0.9969 | 0.9970 | 0.9971 | 0.9972 | 0.9973 | 0.9974 |
| 2.8 | 0.9974 | 0.9975 | 0.9976 | 0.9977 | 0.9977 | 0.9978 | 0.9979 | 0.9979 | 0.9980 | 0.9981 |
| 2.9 | 0.9981 | 0.9982 | 0.9982 | 0.9983 | 0.9984 | 0.9984 | 0.9985 | 0.9985 | 0.9986 | 0.9986 |
| 3.0 | 0.9987 | 0.9987 | 0.9987 | 0.9988 | 0.9988 | 0.9989 | 0.9989 | 0.9989 | 0.9990 | 0.9990 |
| 3.1 | 0.9990 | 0.9991 | 0.9991 | 0.9991 | 0.9992 | 0.9992 | 0.9992 | 0.9992 | 0.9993 | 0.9993 |
| 3.2 | 0.9993 | 0.9993 | 0.9994 | 0.9994 | 0.9994 | 0.9994 | 0.9994 | 0.9995 | 0.9995 | 0.9995 |
| 3.3 | 0.9995 | 0.9995 | 0.9995 | 0.9996 | 0.9996 | 0.9996 | 0.9996 | 0.9996 | 0.9996 | 0.9997 |
| 3.4 | 0.9997 | 0.9997 | 0.9997 | 0.9997 | 0.9997 | 0.9997 | 0.9997 | 0.9997 | 0.9997 | 0.9998 |
Negative z-scores and symmetry
Use Φ(−z) = 1 − Φ(z). For z = −1.23, P(Z ≤ −1.23) = 1 − 0.8907 = 0.1093. The area above −1.23 is 0.8907.
A minus sign changes the side of the mean; it does not produce a negative probability. Avoid reading row −1.2 and adding 0.03 as if that represented −1.23: it represents −1.17 under ordinary addition. Use the negative lookup or the symmetry rule explicitly.
Choose the region before calculating
| Requested region | Formula |
|---|---|
| Below a | Φ(a) |
| Above a | 1 − Φ(a) |
| Between a and b, a < b | Φ(b) − Φ(a) |
| Outside a to b | Φ(a) + 1 − Φ(b) |
| Two symmetric tails beyond ±c | 2[1 − Φ(c)] |
For −1 < Z < 1.5, use 0.9332 − 0.1587 ≈ 0.7745. For |Z| > 1.96, use 2(1 − 0.9750) ≈ 0.0500. Use unrounded values when available; differences in the final digit can come from subtracting rounded table entries.
Critical values and percentiles
| Purpose | Cumulative probability | Positive z cutoff |
|---|---|---|
| 90th percentile | 0.900 | 1.2816 |
| 95th percentile / one upper tail of 5% | 0.950 | 1.6449 |
| Central 95% interval / two tails totaling 5% | 0.975 | 1.9600 |
| 99th percentile | 0.990 | 2.3263 |
| Central 99% interval | 0.995 | 2.5758 |
The 95th percentile and the upper cutoff of a central 95% interval are different. The latter leaves 2.5% above the upper cutoff and 2.5% below the lower cutoff.
Worked example from an original measurement
Assume X follows a normal model with mean 100 and SD 15. For x = 130, z = (130 − 100)/15 = 2. The table gives P(X ≤ 130) ≈ 0.9772; P(X > 130) ≈ 0.0228.
For a mean of n independent observations, use the standard error σ/√n, not the SD of individual outcomes. If σ is estimated from the same sample, a mean test generally uses the t distribution.
Practice
A normal model has mean 50 and SD 8. Find the probability above 62.
Show the solution
z = (62 − 50)/8 = 1.5. Φ(1.5) = 0.9332, so the upper tail is 0.0668, or 6.68%. Reporting 0.9332 would answer the opposite question.
Reference and related tools
NIST’s normal distribution reference defines the cumulative normal function. Read the z-score lesson, explore the normal distribution, or use the z-score calculator. Browser print includes this reference grid; interactive controls are omitted from the printed version.